Tag Archives: chocolate feast

HackerRank Çözümleri – Chocolate Feast

HackerRank içerisinde bulunan “Chocolate Feast” sorusunun açıklaması ve çözümü. Bu soruda size verilen bir çikolata dükkanı için, belirli bir sayıda çikolata kabı getirdiğinizde belirli bir sayıda çikolata barı alabileceğiniz, belirli bir sayıda çikolata ile maksimum promosyonlar ile birlikte kaç adet çikolata yiyebileceğinizi hesaplamanız isteniyor.

► HackerRank – Chocolate Feast: https://www.hackerrank.com/challenges/chocolate-feast/problem

► Problem açıklaması:

Little Bobby loves chocolate. He frequently goes to his favorite 5&10 store, Penny Auntie, to buy them. They are having a promotion at Penny Auntie. If Bobby saves enough wrappers, he can turn them in for a free chocolate.

Example

n = 15

c = 3

m = 2

He has 15 to spend, bars cost 3, and he can turn in 2 wrappers to receive another bar. Initially, he buys 5 bars and has 5 wrappers after eating them. He turns in 4 of them, leaving him with 1, for 2 more bars. After eating those two, he has 3 wrappers, turns in 2 leaving him with 1 wrapper and his new bar. Once he eats that one, he has 2 wrappers and turns them in for another bar. After eating that one, he only has 1 wrapper, and his feast ends. Overall, he has eaten 5 + 2 + 1 + 1 = 9 bars.

Function Description

Complete the chocolateFeast function in the editor below.

chocolateFeast has the following parameter(s):

int n: Bobby’s initial amount of money

int c: the cost of a chocolate bar

int m: the number of wrappers he can turn in for a free bar

Returns

int: the number of chocolates Bobby can eat after taking full advantage of the promotion

Note: Little Bobby will always turn in his wrappers if he has enough to get a free chocolate.

Sample Input

STDIN Function

—– ——–

3 t = 3 (test cases)

10 2 5 n = 10, c = 2, m = 5 (first test case)

12 4 4 n = 12, c = 4, m = 4 (second test case)

6 2 2 n = 6, c = 2, m = 2 (third test case)

Sample Output

6

3

5